00:01
First of all, let's have a look what all is given in the problem.
00:05
Given is electronic configuration of the element is given.
00:10
The electronic configuration that is given is argon 3d6 4s2.
00:18
This is the electronic configuration that is given and what all we are supposed to find.
00:24
In the first part, we need to find the period number.
00:27
In second part we have to find the group number next we have to find the kind of element it is like whether it is a metal non -metal or metalloid so this we have to find and the last one we have to find the number of unpaired electrons number of unpaired electrons we have to find out so let's look at one by one with all of these the first one first thing is that let's write the electronic configuration again, argon 3d6, 4s2.
01:06
First, let's write the atomic number for this.
01:10
Argon has 18 electrons, 18 plus 220 and plus 6, 26.
01:15
So the atomic number is 26, so we know that it is fe, iron.
01:22
Now we can, with the help of electronic configuration, we can find out both the period number as well as the group number.
01:31
So let's try to find out period number.
01:36
Let's first find out the period number.
01:39
The highest n value will give us the period number.
01:43
So period number is 4.
01:47
Now we have to find the group number.
01:50
The number of fail in selectron present will give the group number...