A 5 kg block is pulled with a force of 100 N at an angle 150 to the horizontal. What is the magnitude of the normal force on the block?
Added by Felix L.
Step 1
First, we need to resolve the force into its horizontal and vertical components. The horizontal component of the force can be calculated as F_horizontal = F * cos(theta), where theta is the angle between the force and the horizontal (150 degrees in this case). So, Show more…
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