00:01
High students in this question, a stainless steel is been heated using a particular furnace and we are to find out the final temperature, t of t, associated with this stainless scale.
00:10
Now in order to solve this question, a few data has been given, which include thickness of the steel, which is taken as capital l and its value is taken as 5 into 10 raise to minus 3 meter.
00:21
The thermal conductivity is taken as k which is equal to 21 watt per meter kelvin.
00:28
The density is taken as r which is equal to 8 ,000 kilogram per meter cube.
00:35
The specific heat is taken as cp which is equal to 570 joules per kilogram kelvin.
00:43
The velocity of the steel is taken as v which is equal to 1 .10 .5 .2 meter per second.
00:50
Now the length of the furnace in this case is taken as small letter d which is equal to 3 meter.
00:55
So the air temperature is taken as t infinity which is equal to 900 degrees celsius.
01:02
The initial temperature of the steel is taken as ti which is equal to 20 degrees celsius and finally the heat transfer coefficient is taken as h which is equal to 80 watt per meter square kelvin.
01:16
Now first we can find out the value of characteristic length lc of the furnace which will be equal to the ratio of volume b divided by area a.
01:25
And in this case the volume b will be equal to the product of thickness into area a divided by 2...