We can use the right triangle formed by the cable, the vertical distance of 1.5 m, and the horizontal distance of 1.5 m. Using the tangent function, we have:
$\tan(\theta) = \frac{1.5}{1.5} = 1$
$\theta = \tan^{-1}(1) = 45^\circ$
Now, we can analyze the forces
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