00:01
In this question we have three parts.
00:02
Let's try the values first of all those are given to us in the question.
00:05
So like first of all, mass is given to us that is equal to 5 kilogram and downward acceleration is equal to 3 .8 meters per second per second.
00:18
Okay, now for first part, that is part a.
00:24
If we draw the free body diagram, so this will be the direction of the normal force and this will be the direction of acceleration this will be the direction of mg sign theta this will be the direction of its own weight that is mg this is theta this is equal to mg cross theta okay now first of all in this diagram we can see that uh all the forces acting on the object placed on an incline surface is as shown so that is that is basically we have to show in this part of the question so let's suppose this is the center of the most central point of the block.
01:46
This is mg sine theta.
01:58
This is the normal.
02:11
And this is the acceleration.
02:37
This is the direction of mg.
02:44
This is the direction of mg cost theta.
02:53
This is theta.
02:54
So this is all we had to show.
02:55
Now, this is our answer for part a.
02:58
Now for part b, the force acting on block in direction of acceleration is mg sine theta, that is equal to m .a...