00:01
50 kilogram child stands at the rim of america around a radius 1 .5 meters redittance in an angle at speed of 3 radiance per second.
00:10
So let's say this is america around.
00:11
This child is standing right here.
00:17
And we have the centrifugal force, fc.
00:23
We have the friction of force, fr, it's called to ff.
00:30
This is the center rotation.
00:32
Let's return like this.
00:35
At three radiance per second i won't find first of all the minimum force between the feet on the floor of the carousel that is required to keep in circular path which is going to be the central petal force which is provided by the friction on force there so we have fc is equal to f f f and fc is emm square of error is equal to friction or force and this can be written can also be written as m omega squared r because v is equal to omega r so substituting that and that in there will give us that and so we can simply solve our friction on force friction on force is equal to the mass is 50 kilograms times the omega that's the angle of velocity three radiance per second square that multiplied by the radius is 1 .5 meters.
01:44
This is equal to 675 newtons.
01:53
This is for i.
01:56
Now for the second one, what minimum question of the static friction is required.
02:01
So the percussion is the static friction.
02:03
The friction our force is equal to mu times the normal force.
02:07
Here we have the normal force on the child acting upwards, the weight of the child acting downwards...