A 500 -W heating coil designed to operate from 110 V is made of Nichrome wire 0.500 mm in diamet

Name: A 500 -W heating coil designed to operate from 110 V is made of Nichrome wire 0.500 mm in diameter. (a) Assuming the resistivity of the Nichrome remains constant at its 20.0^∘C value, find the length of wire used. (b) What If? Now consider the variation of resistivity with temperature. What power is delivered to the coil of part (a) when it is warmed to 1200^∘C ?
Uploaded: 2021-11-11T15:22:56-08:00
Duration: 6 min 26 s
Channel: Vishal Gupta
Description: A 500 -W heating coil designed to operate from 110 V is made of Nichrome wire 0.500 mm in diameter. (a) Assuming the resistivity of the Nichrome remains constant at its 20.0^∘C value, find the length of wire used. (b) What If? Now consider the variation of resistivity with temperature. What power is delivered to the coil of part (a) when it is warmed to 1200^∘C ?

Step 1: Calculate the length of the Nichrome wire used in the heating coil. Given: Power (P) = 5

Question

A 500 -W heating coil designed to operate from 110 $\mathrm{V}$ is made of Nichrome wire 0.500 $\mathrm{mm}$ in diameter. (a) Assuming the resistivity of the Nichrome remains constant at its $20.0^{\circ} \mathrm{C}$ value, find the length of wire used. (b) What If? Now consider the variation of resistivity with temperature. What power is delivered to the coil of part (a) when it is warmed to $1200^{\circ} \mathrm{C} ?$

          A 500 -W heating coil designed to operate from 110 $\mathrm{V}$ is made of Nichrome wire 0.500 $\mathrm{mm}$ in diameter. (a) Assuming the resistivity of the Nichrome remains constant at its $20.0^{\circ} \mathrm{C}$ value, find the length of wire used. (b) What If? Now consider the variation of resistivity with temperature. What power is delivered to the coil of part (a) when it is warmed to $1200^{\circ} \mathrm{C} ?$

Added by Jose Luis S.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Vishal Gupta

11/11/2021

Step 1

Given: Power (P) = 500 W Voltage (V) = 110 V Resistance (R) = 24.2 ohms Resistivity ($\rho$) = $1.50 \times 10^{-6}$ ohm m Diameter of wire = 0.500 mm = 0.0005 m The formula for resistance is: $R = \rho \times \frac{L}{A}$, where $A$ is the cross-sectional area Show more…

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A 500 -W heating coil designed to operate from 110 $\mathrm{V}$ is made of Nichrome wire 0.500 $\mathrm{mm}$ in diameter. (a) Assuming the resistivity of the Nichrome remains constant at its $20.0^{\circ} \mathrm{C}$ value, find the length of wire used. (b) What If? Now consider the variation of resistivity with temperature. What power is delivered to the coil of part (a) when it is warmed to $1200^{\circ} \mathrm{C} ?$