00:01
We're told that we have 500 .0 grams of an unknown metal.
00:10
Its initial temperature is 153 .0 degrees celsius.
00:18
It's dropped into an ice water mixture.
00:35
When it's 109 .5 grams of ice melts and some ice remains, so all that happened here is some ice melted.
00:53
And we're asked to find the specific heat of the metal in j over g degree c.
01:10
We're going to work on this as q of the water is equal to q of the metal.
01:16
So the first thing we're going to do is q, i should say, of the ice.
01:29
Q of the ice is going to be 109 .5 grams because that's how much melted.
01:34
And let me go lump up the cup, the molar heat or fusion of ice.
01:38
Or heat of fusion ice.
01:45
Let's see what my units pop in.
01:47
I get jates, i get three, three, oops, i get three, three, three point five, jules per gram.
02:02
See if i'm given anything else in this problem that i need to.
02:05
What is it supposed to, given the molar heat.
02:08
Okay.
02:10
So i have 109 .5 times 333 .55.
02:16
So i have 36 ,524 joules.
02:24
That's how many joules of heat were used to melt the ice.
02:32
Now we know that q of ice is equal to q of the metal.
02:36
So now i'm going to use q equals, let me switch colors.
02:46
And we know delta t will be 153 .0 degrees c.
02:52
And we know the mass in the q.
02:54
So we're going to solve for c.
02:55
C equals q over m delta t.
03:02
So c will equal, that's my specific heat, 36, 524 joules, divided by 500 .0 .0 grams, divided by 153 .0 degrees c.
03:19
And that will equal 36, 524, divided by 500, divided by 153 .8, will give me 0 .475, and then my units are j over g degrees c.
03:41
My next step will you be used to my given molar.
03:46
I'm given one more thing.
03:48
Let's go to this.
03:50
Let's go to this...
