00:01
So to solve for this, the heat loss by aluminum will be given to the heat gained by water.
00:11
So i will assume that we have water in our calorimeter.
00:14
Plus the heat gain by the calorimeter.
00:17
So heat loss will be negative and we should have here change in temperature.
00:22
So mass multiplied by the specific heat capacity of aluminum, multiply by the change in temperature.
00:28
And then we have here mass multiplied by the specific heat capacity of water, and then the change in temperature in water, and then the heat gained by the calorimeter, which is our unknown.
00:38
So rearranging this, we'll plug in the information that we have.
00:43
Mass of aluminum is 49 .9 .50 grams.
00:47
The specific heat of aluminum is not given here, but this could be looked up in standard difference materials, and it's equivalent to 0 .89, joules per grams, degrees celsius.
00:56
Then the change in temperature, we know that the final temperature of the mixture is 35 .5 degrees celsius, but we don't have here the initial temperature of aluminum.
01:06
So i'm just going to write ci.
01:08
This is aluminum...