a 515 kg roller coaster is at the bottom of loop with radius of 10m it the speed at the bottom of the loop is 20m/s what is the force of the track pushing up ont the vehicle at this point?
Added by Karen S.
Step 1
This is given by the formula F = m*g, where m is the mass of the roller coaster and g is the acceleration due to gravity (approximately 9.8 m/s^2). F = 515 kg * 9.8 m/s^2 = 5047 N. This is the force pulling the roller coaster downwards. Show more…
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