6. A 54.7g piece of metal heated to 90.3°C and dropped into...

Name: 6. A 54.7g piece of metal heated to 90.3°C and dropped into a calorimeter containing 71.2g of water at 18.6°C. The calorimeter constant is 13.5 J/°C. The final temperature of the metal, the water and the calorimeter is 28.5°C. Calculate the specific heat capacity of the metal.
Uploaded: 2022-08-10T08:37:24-08:00
Duration: 3 min 46 s
Channel: Dominique Jan Tan
Description: 6. A 54.7g piece of metal heated to 90.3°C and dropped into a calorimeter containing 71.2g of water at 18.6°C. The calorimeter constant is 13.5 J/°C. The final temperature of the metal, the water and the calorimeter is 28.5°C. Calculate the specific heat capacity of the metal.

6. A 54.7g piece of metal heated to 90.3°C and dropped into a calorimeter containing 71.2g of water at 18.6°C. The calorimeter constant is 13.5 J/°C. The final temperature of the metal, the water and the calorimeter is 28.5°C. Calculate the specific heat capacity of the metal.

Transcript

00:01 Heat is a form of energy that flows from a hotter to a colder body.

00:04 If we neglect heat loss to the surroundings, then the heat that is released by the hotter object plus the heat that is absorbed by the colder object must be equal to zero.

00:15 In this problem, we're given with a metal that is heated to a temperature of 97 .2 degrees celsius.

00:24 So let's say metal, m, its initial temperature, ti, is equal to 97 .2 degrees celsius.

00:32 Its mass is also given to be equal to 26 grams.

00:38 Now, this metal is placed in a calorimeter that contains water, which mass is equal to 126 grams.

00:50 Initially, the temperature in the calorimeter is at the temperature of 26 .6 degrees celsius.

00:58 When equilibrium is established, the final temperature of both water and the metal is, to 29 degrees celsius thinking that the specific heat of water is equal to 4 .18 joules per gram degrees celsius and that no heat is lost to the surrounding and if we may also add there is also no heat that is absorbed by the color meter we want to find the heat capacity per gram or simply that's the specific heat of the metal so as the metal is the hotter object, then we have qm plus qw, which is the colder object, well, water is the colder object, so that's qw equals 0.

01:46 So the amount of heat that is involved when the temperature of the substance changes is quantified as product of the mass, the specific heat, and the difference in the temperature which we solve as the, and the change in the temperature, which we solve as the, the difference between the final temperature and the initial temperature...

Question

6. A 54.7g piece of metal heated to 90.3°C and dropped into a calorimeter containing 71.2g of water at 18.6°C. The calorimeter constant is 13.5 J/°C. The final temperature of the metal, the water and the calorimeter is 28.5°C. Calculate the specific heat capacity of the metal.

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