A 55 kg box rests on a horizontal surface. The coefficient of kinetic friction between the box in the surface is .30. A 140 N force is applied to the box what is the acceleration of the box?
Added by Julian C.
Step 1
Given: Mass of the box (m) = 55 kg Coefficient of kinetic friction (μ) = 0.30 Acceleration due to gravity (g) = 9.8 m/s^2 Friction force (F_friction) = μ * m * g F_friction = 0.30 * 55 kg * 9.8 m/s^2 F_friction = 161.7 N Show more…
Show all steps
Your feedback will help us improve your experience
Dwijendra Rao and 82 other Physics 101 Mechanics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
A 55-kg box rests on a horizontal surface. The coefficient of static friction between the box and the surface is 0.30, and the coefficient of kinetic friction is 0.20. What horizontal force must be applied to the box to cause it to start sliding along the surface?
Prabhu R.
Friction: A 55-kg box rests on a horizontal surface. The coefficient of static friction between the box and the surface is 0.30, and the coefficient of kinetic friction is 0.20. What horizontal force must be applied to the box to cause it to start sliding along the surface?
Supratim P.
A $50-\mathrm{kg}$ box rests on the floor. The coefficients of static and kinetic friction between the bottom of the box and the floor are 0.70 and 0.50 , respectively. (a) What is the minimum force a person needs to exert on the box to start it sliding? (b) After the box starts sliding, the person continues to push it, exerting the same force. What is the acceleration of the box?
Recommended Textbooks
University Physics with Modern Physics
Physics: Principles with Applications
Fundamentals of Physics
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD