00:01
Hello everyone we are going to understand this question here given in the question given mass of bowling mass of bowling that is represented by m1 which is equal to 5 .5 kilogram initial speed initial speed of bowling that is represented by u1 which is 9 .0 meter per cent second.
00:58
Let final speed be v1.
01:01
Let final speed be v1.
01:11
Mass of bowling pin, mass of bowling pin, that is represented by m2, which is 0 .85 kilogram.
01:42
And initial speed of pin, initial speed of pin, that is represented by u2 which is equal to 0 and final speed of pin final speed of pin that is represented by v2 which is given 15 .0 meter per second now applying conservation of linear momentum now applying conservation of linear momentum now applying conservation of so we can write m1 u1 m1 into u1 plus m2 into u2 is equal to m1 into v1 plus m2 now substituting the value in this value of m1 is 5 .5 into value of u1 is 9 plus value of m2 is 0 .85 into initial speed is 0 is equal to value of m1 is 5 .5 into v1 plus 0 .85 into 15.
03:46
Now doing further calculation, so we can write 5 .5 into v1 is equal to 5 .5 into 9 minus 0 .85 into 15.
04:08
Now again we can write v1 is equal to 36 .75 upon 5 .5 meter per second.
04:23
After doing further calculation we will get v1 is equal to 6 .68 meter per second...