00:01
Hi, so to solve for this, since we know that the mixture is in an insulated container, that means the amount of heat lost by zinc will be equivalent to the amount of heat gained by the liquid in the container.
00:15
So we have heat lost by zinc since the piece of zinc is hotter compared to the liquid sample in the container.
00:28
So this will be heat gained by a known liquid.
00:35
Just gonna write liquid.
00:37
Then we have negative mass specific heat change in temperature, and this is for zinc.
00:42
And then we have positive mass specific heat and then the change in temperature for the unknown liquid.
00:49
So to determine the identity of the liquid, we will solve for the specific heat capacity of the liquid.
00:56
So the liquid will isolate our unknown, the specific heat capacity of the liquid will be equivalent to negative mass specific heat change in temperature.
01:04
This is for the zinc sample divided by mass and then the change in temperature for the liquid.
01:13
Plug in the given information, mass of zinc is 57 .1 grams and then the specific heat capacity of zinc is 0 .388 joules per gram degree celsius.
01:29
The change in temperature, this is final minus the initial temperature.
01:33
The final temperature, the equilibrium temperature is 36 .7 degrees celsius...