00:01
Hi, so to solve for this, let us write first the balance equation for this reaction.
00:06
We have silver nitrate, agno3 plus barium chloride, bacl2.
00:12
Then the products, silver chloride plus barium nitrate, no3, 2.
00:20
So to balance this, we just need to write here 2 and then 2 in silver chloride.
00:26
Now we're solving for percent yield, so we will calculate for the theoretical yield first.
00:33
Theoretical yield is the amount of product formed using stoichiometry.
00:38
So mass of silver chloride, agcl, if we have 5 .95, this is grams of silver nitrate, convert to moles by the molar mass of agno3, that's 169 .87, this is grams, then we have here moles of silver nitrate...