Question

A 6-pole, 3.0 hp 120V DC lap-wound shunt motor has 960 conductors in the armature. It takes 25.0 A from the supply at full load. The armature resistance is 0.752 Î©, flux/pole = 10.0 mWb, and the field winding current is 1.20 A. Find the speed and torque.

Name: a 6 pole 30 hp 120v dc lap wound shunt motor has 960 conductors in the armature it takes 250 a from the supply at full load armature resistance is 0752 fluxpole100 mwb field winding current 54565
Uploaded: 2023-05-07T16:15:20-08:00
Duration: 2 min 29 s
Channel: Sri K
Description: a 6 pole 30 hp 120v dc lap wound shunt motor has 960 conductors in the armature it takes 250 a from the supply at full load armature resistance is 0752 fluxpole100 mwb field winding current 54565

          A 6-pole, 3.0 hp 120V DC lap-wound shunt motor has 960 conductors in the armature. It takes 25.0 A from the supply at full load. The armature resistance is 0.752 Î©, flux/pole = 10.0 mWb, and the field winding current is 1.20 A. Find the speed and torque.

Added by April W.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Sri K

05/07/2023

Step 1

We can use the formula: E_b = V - I_a * R_a Where V is the supply voltage, I_a is the armature current, and R_a is the armature resistance. We know that the total current drawn from the supply is 25.0 A, and the field winding current is 1.20 A. So, the armature Show more…

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A 6-pole, 3.0 hp 120V DC lap-wound shunt motor has 960 conductors in the armature. It takes 25.0 A from the supply at full load. The armature resistance is 0.752 Î©, flux/pole = 10.0 mWb, and the field winding current is 1.20 A. Find the speed and torque.