A 60.0 W incandescent light bulb is only 11 % efficient at producing light (the rest is converted into thermal energy). The light bulb is operating for 2.0 h. Calculate how much energy is input to the bulb and how much energy is output as light energy. (11.1)
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We know that the power of the bulb is 60.0 W and it operates for 2.0 hours. We can use the formula: Energy = Power × Time To convert hours to seconds, we multiply by 3600 (since there are 3600 seconds in an hour). So, the time in seconds is 2.0 × 3600 = 7200 Show more…
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