Question

A 64 KB 2-way set-associative cache is word-addressable and contains 64 byte lines. Memory addresses are 42-bit wide. How wide are the tags in this cache? Assume 1KB is 1024 Bytes

          A 64 KB 2-way set-associative cache is word-addressable and contains 64 byte lines. Memory addresses are 42-bit wide.
How wide are the tags in this cache?
Assume 1KB is 1024 Bytes

Added by Valerie C.

Computer Science and Information Technology

Trishna Knowledge Systems 2018 Edition

Instant Answer

Solved by Expert Supreeta N

05/26/2023

Step 1

Since the cache is 64KB and each line is 64 bytes, we can calculate the total number of lines as follows: 64KB = 64 * 1024 = 65536 bytes Total number of lines = 65536 bytes / 64 bytes per line = 1024 lines Show more…

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A 64KB2-way sel-associative cache is word-addressable and contains 64 byte lines. Memory addresses are 42-bit wide. How wide are the rags in this cache? Assume IKB is 1024 Bytes A 64 KB 2-way set-associative cache is word-addressable and contains 64 byte lines. Memory addresses are 42-bit wide How wide are the tags in this cache? Assume 1KB is 1024 Bytes