A 65 -kg diver jumps off of a 10.0 -m tower. a. Find the diver's velocity when he hits the water. b. The diver comes to a stop $2.0 \mathrm{m}$ below the surface. Find the net force exerted by the water.
Added by Donna G.
Step 1
Given: Mass of diver, m = 65 kg Height of tower, h = 10.0 m Acceleration due to gravity, g = 9.8 m/s^2 Using the principle of conservation of energy: Initial potential energy = Final kinetic energy mgh = 0.5mv^2 65 kg * 9.8 m/s^2 * 10.0 m = 0.5 * 65 kg * v^2 v = Show more…
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