A 65-kg skydiver jumps out of an airplane and falls 320 m, reaching a maximum speed of 69 m/s before opening her parachute. Assuming the force of air resistance is constant, what is the magnitude of the force of air resistance, in newtons, on her?
Added by Eugenia L.
Step 1
We can use the equation of motion: v^2 = u^2 + 2as where v is the final velocity (69 m/s), u is the initial velocity (0 m/s), a is the acceleration, and s is the distance (320 m). Rearranging the equation, we have: a = (v^2 - u^2) / (2s) a = (69^2 - 0^2) / (2 Show more…
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A parachutist relies on air resistance (mainly on her parachute) to decrease her downward velocity. She and her parachute have a mass of 55.0 $\mathrm{kg}$ , and at a particular moment air resistance exerts a total upward force of 620 $\mathrm{N}$ on her and her parachute. (a) What is the weight of the parachutist? $(\mathrm{b})$ Draw a free-body diagram for the parachutist (see Section $4.6 ) .$ Use that diagram to calculate the net force on the parachutist. Is the net force upward or downward? (c) What is the acceleration (magnitude and direction) of the parachutist?
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