00:01
Hello, we have to solve the following problem.
00:02
A capacitor with the capacitance of 6 .30 microferds is initially uncharged and it's connected in ceri with a resistor of 4 ,700 tons and emf of 509 volts.
00:25
We have to calculate first voltage drop across the resistor when time is zero seconds.
00:37
Let's do the same.
00:37
So first of all let's write down the equation which connects emf to the voltage of the resistor so that it goes to the voltage of the resistor plus the voltage of the capacitor and when voltage of the capacitor as a function of time is emf times one minus exponent of negative time over time constant therefore when time at 0 seconds, voltage of the capacitor is 0 volts and therefore voltage of the resistor at 0 seconds is emf which is 509 volts.
01:31
That is soft.
01:33
Now it's time to move on to the next question.
01:37
We have to calculate the charge of the capacitor when time is 0 and this charge qc equals to so, emf times capacitance times one minus exponent of negative t over tau.
01:55
Therefore, at zero seconds, this charge is zero columns.
02:02
Now, let's move on to the next question.
02:04
Question 3.
02:10
We have to calculate current through the resistor at 0 seconds.
02:16
And this current, as a function of time, is a derivative of charge at the capacity.
02:23
As a function of time...