Question

A 68-kg ice hockey player standing on a frictionless sheet of ice throws a 5.0-kg bowling ball horizontally with a speed of 3.4 m/s. With what speed does the hockey player recoil? An MSU linebacker of mass 112.0 kg sacks a UM quarterback of mass 86.0 kg. Just after they collide, they are momentarily stuck together, and both are moving at a speed of 3.10 m/s. If the quarterback was at rest just before he was sacked, how fast was the linebacker moving just before the collision? 

          A 68-kg ice hockey player standing on a frictionless sheet of ice throws a 5.0-kg bowling ball horizontally with a speed of 3.4 m/s. With what speed does the hockey player recoil? An MSU linebacker of mass 112.0 kg sacks a UM quarterback of mass 86.0 kg. Just after they collide, they are momentarily stuck together, and both are moving at a speed of 3.10 m/s. If the quarterback was at rest just before he was sacked, how fast was the linebacker moving just before the collision?
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University Physics with Modern Physics
University Physics with Modern Physics
Hugh D. Young 14th Edition
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A 68-kg ice hockey player standing on a frictionless sheet of ice throws a 5.0-kg bowling ball horizontally with a speed of 3.4 m/s. With what speed does the hockey player recoil? An MSU linebacker of mass 112.0 kg sacks a UM quarterback of mass 86.0 kg. Just after they collide, they are momentarily stuck together, and both are moving at a speed of 3.10 m/s. If the quarterback was at rest just before he was sacked, how fast was the linebacker moving just before the collision?
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Transcript

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00:01 Hi.
00:01 Here in this given problem, mass of the ice hockey forward, that is m1 is equal to 70 .0 kilogram.
00:23 His initial velocity v1i, that is given as 5 .5 meter per second and this is due north.
00:41 He is sliding due north then mass of the defender that is given as m2 is equal to hundred and ten kilogram and his initial velocity the velocity with which he is sliding v2 i that is 4 .0 meter per second this is due south so we will take it to be negative now, as both become intertwined after the collision, so both will be moving with the same velocity, which we have to find...
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