A 68.0 kg skater moving initially at 2.25 m/s on rough horizontal ice comes to rest uniformly in 4.00 s due to friction from the ice.
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$m = 68.0 \, \text{kg}$ $v_i = 2.25 \, \text{m/s}$ $v_f = 0 \, \text{m/s}$ $t = 4.00 \, \text{s}$ We can find the acceleration using the equation: Show more…
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