A 7 kg block is pushed across a horizontal surface by the 45 N force shown in the diagram below. The block moves at a constant velocity of 2 m/s. How big is the coefficient of kinetic friction between the block and the surface?
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mg = 7 kg * 9.8 m/s^2 = 68.6 N Vertical component of the applied force = 45 N * sin 30° = 22.5 N Net vertical force = 68.6 N + 22.5 N = 91.1 N Show more…
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