A 70 kg rock lies at the bottom of a lake. Its volume is 3.0 x 10^-3 m^3. How much force is needed to lift it?
Added by Steven A.
Step 1
8 m/s^2 Weight = Mass x Acceleration due to gravity Weight = 70 kg x 9.8 m/s^2 Weight = 686 N Show more…
Show all steps
Your feedback will help us improve your experience
Pritesh Ranjan and 99 other Physics 101 Mechanics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
A 75.0 -kg rock lies at the bottom of a pond. Its volume is $3.10 \times 10^{4} \mathrm{~cm}^{3}$. How much force is needed to lift the rock?
Fluids
Buoyancy
A 70 kg ancient statue lies at the bottom of the sea. Its volume is 3.0 *10^4 cm^3. How much force is needed to lift it? [392.40 N]
Prabhu R.
A pump lifts water from a lake to a large tank $20 \mathrm{~m}$ above the lake. How much work against gravity does the pump do as it transfers $5.0 \mathrm{~m}^{3}$ of water to the tank? One cubic meter of water has a mass of $1000 \mathrm{~kg}$.
Recommended Textbooks
University Physics with Modern Physics
Physics: Principles with Applications
Fundamentals of Physics
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD