00:02
Hi, here in this given problem, the value of charge, this is 7 .1 microculum, it is moving in a magnetic field which is given in vector form as minus 24 i cap millie tesla.
00:24
There is an electric field also in vector form.
00:27
This says 300 j cap.
00:30
Volt per meter and the velocity of this charge particle in vector form this is 15 i cap minus 12 j cap plus 5 .4 k cap kilometer per second this is so it may be written as 15 i cap minus 12 j cap plus 5 .4 k cap into 10 ratio to the power 3 meter per second so electrostatic force experienced by this charge particle will be given by the expression q charge q times the electric field so here it will be 7 .1 microculem or 7 .1 into 10 to the power minus 6 coulum multiplied by the electric field which is 300 j cap volt per meter so finally this electrostatic force is calculated to be equal to 2 .13 into 10 raised to the power minus 3 j cap volt per meter means electrostatic force is along y -axis positive y -axis then magnetic lawrence force experienced by the same charge particle that is given by the expression charge q times the cross product of velocity vector with the magnetic field vector again for the charge this is 7 .1 into 10 to the power minus 6 then cross product of velocity vector 15 i cap minus 12 j cap plus 5 .4 k cap into 10 to the power 3 which which we have used to convert kilometer per second to meter per second.
02:34
And then multiplied by magnetic field vector which is minus 24 i cap and that was millitessla.
02:43
So this is 10 to the power minus 3 tesla.
02:47
This 10 to the power plus 3 and 10 to the power minus 3 will be cancelled.
02:51
Then if we cross multiply this i cap with i and j and k cap respectively we will get and first of all, we multiply 7 .1 with this 24 minus 24 and it comes out to be equal to minus 0 .170 into 10 raised to the power minus 3...