00:01
Here in this problem we have been given that 75 grams of ice is placed inside the water, which is having mass of 825 grams.
00:18
So this is the mass of water.
00:19
Let's take it as m2 and let's take this as m1.
00:23
And the water is at a temperature of 25 degrees celsius.
00:31
And the ice here is having the temperature as 0 degrees celsius.
00:38
So as this ice is placed within water, we need to figure out the temperature that will be of the mixture.
00:50
So figure out the temperature of the mixture, in fact, at the final point of course.
00:54
So here there will be heat transmission and that heat transmission will first cause this ice to melt, melt and then rise the temperature of this ice.
01:07
So here we will use the concept of latent heat and the specific heat and we're going to use the value for the specific heat of water as 4186 unit will be jule per kg per degree celsius and we will use the latent heat of fusion that will be 10 raised to 5 jules per kg.
01:39
So this will be the latent heat of fusion we're going to use.
01:45
So here as we can see, let's suppose in the mixture, the final temperature is t which is needed to be determined.
01:53
So first water will lose some heat because definitely its temperature will be lowered.
02:00
So that heat can be computed using m2 times the specific heat of water times the change in temperature that will be t2 minus t.
02:11
So this is the expression for getting the heat when there is temperature rise or basically when there is temperature change...