A 75-kg man is at rest on ice skates. A 0.20-kg ball is thrown to him. The ball is moving horizontally at $25 \mathrm{m} / \mathrm{s}$ just before the man catches it. How fast is the man moving just after he catches the ball?
Added by Gina R.
Step 1
First, we need to find the initial momentum of the system. Since the man is at rest, his initial momentum is 0. The initial momentum of the ball is its mass times its velocity. Initial momentum of the ball = mass of the ball × velocity of the ball = 0.20 kg × 25 Show more…
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