A 7kg block slides down a 30 degree slope at a constant velocity of 2 m/s. How big is the force of friction acting on the block?
Added by William O.
Step 1
We can use the formula Fg = mg, where m is the mass of the block and g is the acceleration due to gravity (9.8 m/s^2). Fg = (7 kg)(9.8 m/s^2) = 68.6 N Show more…
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