Question

A 8.50 kg object has the given x and y acceleration components.\ $a_x = (0.47 \frac{m}{s^2}) + (0.77 \frac{m}{s^3})t$\ $a_y = (11.1 \frac{m}{s^2}) - (0.63 \frac{m}{s^3})t$\ What is the magnitude $F_{net}$ of the net force acting on the\ object at time $t = 4.87 s$?\$F_{net} = $\\ What is the angle $\theta$ of the net force at this same time?\Enter your angle in degrees measured counter-clockwise from\ the $+x$ axis.\$\theta = $

Name: A 8.50 kg object has the given x and y acceleration components.ax = (0.47 (m)/(s^2)) + (0.77 (m)/(s^3))tay = (11.1 (m)/(s^2)) - (0.63 (m)/(s^3))tWhat is the magnitude Fnet of the net force acting on theobject at time t = 4.87 s?$Fnet = What is the angleθof the net force at this same time? your angle in degrees measured counter-clockwise fromthe+xaxis.$θ =
Uploaded: 2023-10-07T02:02:37-08:00
Duration: 1 min 22 s
Channel: Timothy James
Description: A 8.50 kg object has the given x and y acceleration components.ax = (0.47 (m)/(s^2)) + (0.77 (m)/(s^3))tay = (11.1 (m)/(s^2)) - (0.63 (m)/(s^3))tWhat is the magnitude Fnet of the net force acting on theobject at time t = 4.87 s?$Fnet = What is the angleθof the net force at this same time? your angle in degrees measured counter-clockwise fromthe+xaxis.$θ =

          A 8.50 kg object has the given x and y acceleration components.\
$a_x = (0.47 \frac{m}{s^2}) + (0.77 \frac{m}{s^3})t$\
$a_y = (11.1 \frac{m}{s^2}) - (0.63 \frac{m}{s^3})t$\
What is the magnitude $F_{net}$ of the net force acting on the\
object at time $t = 4.87 s$?\$F_{net} = $\\
What is the angle $\theta$ of the net force at this same time?\Enter your angle in degrees measured counter-clockwise from\
the $+x$ axis.\$\theta = $

A 8.50 kg object has the given x and y acceleration components.ax = (0.47 (m)/(s^2)) + (0.77 (m)/(s^3))tay = (11.1 (m)/(s^2)) - (0.63 (m)/(s^3))tWhat is the magnitude Fnet of the net force acting on theobject at time t = 4.87 s?$Fnet = What is the angleθof the net force at this same time? your angle in degrees measured counter-clockwise fromthe+xaxis.$θ =

Added by Kenneth M.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Timothy James

10/07/2023

Step 1

87s by plugging in the given time into the acceleration components. a_x = (0.47 m/s^2) + (0.77 m/s^3)(4.87 s) = 3.75 m/s^2 a_y = (11.1 m/s^2) - (0.63 m/s^3)(4.87 s) = 7.71 m/s^2 Show more…

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A 8.50kg object has the given x and y acceleration components. a_(x)=(0.47(m)/(s^(2)))+(0.77(m)/(s^(3)))t a_(y)=(11.1(m)/(s^(2)))-(0.63(m)/(s^(3)))t What is the magnitude F_(net ) of the net force acting on the object at time t=4.87s ? F_(net )= N What is the angle heta of the net force at this same time? Enter your angle in degrees measured counter-clockwise from heta = the +x axis. A 8.50 kg object has the given x and y acceleration components. a=(0.47m+0.7 90-r= What is the magnitude Fnet of the net force acting on the object at time t=4.87 s? Fnet N What is the angle O of the net force at this same time? Enter your angle in degrees measured counter-clockwise from the +x axis. =0