A 90 kg man is standing still on frictionless ice. His friend tosses him a 10 kg ball, which has a horizontal velocity of 20 m/s. After catching the ball, what is the man's velocity?
Added by Nicholas C.
Step 1
Initial momentum = (mass of man * initial velocity of man) + (mass of ball * initial velocity of ball) Initial momentum = (90 kg * 0 m/s) + (10 kg * 20 m/s) Initial momentum = 0 + 200 kg*m/s Initial momentum = 200 kg*m/s Show more…
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