00:01
Hi there, so for this problem, we are told that a nine micropolems positive charge is located at the origin.
00:09
So let's call this the charge q1 and that is equal to nine microcoloms.
00:14
And that is positioned at the origin.
00:17
So that means at the position zero zero.
00:21
And we have another charge q2 and it has a value of five microcolums.
00:27
But and it is also positive charge, and it is located in the position 0 -1.
00:36
Now with that said, we need to find the coordinates of the point where the net electric field strength due to these charges is zero.
00:47
Now, let me just draw this situation that we have in here.
00:53
So this is the ex -adpsis.
00:55
We are going to concentrate just that is in that axis and we have the y axis in here so the charge q1 is here at the center at the position 0 .0 so that's the charge q1 oh sorry well in this case the other charge is position in the y axis so let me just stand this to here and that position is q2.
01:33
Now, we are going to assume that the point where we want the position of the electric field where the electric field is equal to zero.
01:48
So the only way that the electric field is equal to zero when we have two positive charges is when the point is inside, is between the distance between these two charges.
02:04
So let's say that the distance is here.
02:07
So we're going to call, we're going to set that the distance between q1 and the charge um q1 is equal between the point p and the charge q1 is equal to the distance d.
02:26
And then the remaining distance between the charge q2 and the point p is just simply one minus the distance d.
02:38
Because remember that the charge q2 is positioned at 0 .1.
02:46
That's the coordinate for that charge.
02:48
So with that said, we use the equation that we know for the electric field, the net electric field, so that will be columns constant times the charge q1 divided by the distance between that point and the charge q1.
03:04
And this plus columns constant times the charge q2 divided by the distance of separation between the point of interest and the charge q2 to the square.
03:18
So now we want the condition where this net electric field is equal to zero.
03:25
And now we substitute the values in here.
03:28
You can see that we can cancel the columns constant.
03:34
And then we are going to have that this is the charge q1 divided by the separation this, and then this is going to be minus q2 divided by the separation distance to the square.
03:49
Now we substitute this separation distance, so we know that the separation distance r1 is just simply the distance d to the square, and then this is equal to minus the charge q2, this divided by 1 minus d to the square, so now i'm going to pass all of the distances to the left and all of the charges to the right.
04:15
So we're going to have the following.
04:24
In here, of course, consider that one of, we know that when we are calculating in the electric field, we consider that at the point p, there is a positive charge.
04:38
So one of the electric field is, well, both...