A 9.00 V battery is connected to the plates of a capacitor and stores a charge of 27.0 μ C. a. Determine the capacitance. b. The same capacitor is connected to a 12.0 V battery. Determine the charge stored.
Added by Daniela R.
Step 1
00 V and the charge stored is 27.0 μC, we can use the formula for capacitance: \[ C = \frac{Q}{V} \] where: \( C \) = capacitance \( Q \) = charge stored = 27.0 μC = \( 27.0 \times 10^{-6} \) C \( V \) = potential difference = 9.00 V Show more…
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(a) When a 9.00-V battery is connected to the plates of a capacitor, it stores a charge of $27.0 \mu \mathrm{C}$. What is the value of the capacitance? (b) If the same capacitor is connected to a $12.0-V$ battery, what charge is stored?
(a) When a 9.00-V battery is connected to the plates of a capacitor, it stores a charge of 27.0 μC. What is the value of the capacitance? (b) If the same capacitor is connected to a 12.0-V battery, what charge is stored?
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