(a) A 5.00-µF capacitor is connected to an 18.0-V battery. How much energy is stored in the capacitor? ______µJ (b) Had the capacitor been connected to a 6.00-V battery, how much energy would have been stored? ______µJ
Added by Hector L.
Step 1
Substituting the given values, we get: E = (1/2)(5.00 x 10^-6 F)(18.0 V)^2 E = 2.43 µJ Show more…
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