(a) A 6.00-µF capacitor is connected to a 12.0-V battery. How much energy is stored in the capacitor? _______µJ (b) Had the capacitor been connected to a 6.00-V battery, how much energy would have been stored? _______µJ
Added by April B.
Step 1
0-V battery. Given: Capacitance (C) = 6.00 µF = 6.00 x 10^-6 F Voltage (V) = 12.0 V Using the formula for energy stored in a capacitor: E = 0.5 * C * V^2 Substitute the values: E = 0.5 * 6.00 x 10^-6 * (12.0)^2 E = 0.5 * 6.00 x 10^-6 * 144 E = 3.00 x 10^-6 * Show more…
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