00:01
So let us start with the concept which we are going to use here for this question.
00:07
So according to the mirror formula we know that the 1 by f is equals to the 1 by u plus 1 by v where u is the object distance from the mirror, v is the image distance from the mirror and f is the focal length here.
00:24
So since we are given that a concave mirror we must use all the generally known data about the image it creates.
00:31
So for that concave mirror what we have in given let's say this is nothing but what the concave mirror then here is the object let's say.
00:40
So image is forming 4 times larger than the object while the distance between object to that of the image we have in given equals to 6.
00:51
So if we suppose the image is forming at p and sorry object is at p okay means object distance from the mirror is p and image distance from the mirror is nothing but here.
01:06
So by using this we can say that q minus of p this we have given here equals to 6 meter.
01:13
Now according to the concept as we have stated that the image is forming 4 times larger than the object that means to say the magnification we have been given how much that is minus because minus of q by p is nothing but known as the magnification and this will be goes to minus of 4.
01:36
So by using this we get q is equals to the 4 times p.
01:42
Now substituting this in above equation that means here we get 4 p minus p is equals to 6...