00:01
So we know they're going to take 10 items and they're going to accept a shipment if the number of defects, and we'll let x equal the number of defects, is no more than one.
00:19
And so our a, we want to assume that the probability of a defect is equal to 0 .05 or 5%.
00:26
And we want to find here the probability that they accept the shipment.
00:31
So we want to find the probability that x is less than or equal to 1.
00:36
And so this is a binomial setting, and we have n as 10%, and we have this is p, and x is again the number of defects.
00:49
And so we can find the probability of having zero and having one defect.
00:55
And the probability of zero is just setting up that combination of 10 to 0 times 0 .05.
01:01
That's the defect, so we don't want any of those.
01:04
We want all 10 of them to be good, and then versus 10 choose 1 of 0 .05, and we want 1 to be defective, and we want 9 to be good.
01:16
And so when we add these all up, we can also use a binomial cdf to find this and use 10 and 0 .05 and type in 1, and it will actually add those two together.
01:31
So 10 .05 and 1, and that value comes out to be 0 .9139...