00:01
According to the given question, we need to continue here.
00:04
What would be our sample size? so in the first case, population proportion is between 0 .0293 to 0 .0413.
00:16
So at 99 % confidence level, we need to find what would be our sample size.
00:23
So, what would be our zc? this is 2 .576.
00:32
Now, what would be our margin of error? that is z alpha by 2 multiplied by under root of p cap u cap divided by n.
00:49
So, we need to continue here for sample size this must be capital n we need to continue here so that is cap value is so pk plus margin of error would be we need to continue here upper bound value is given and lower bound value is pk minus margin of error 0 .0293 so 2p cap is equals to this is our population proportion 0 .0413 plus 0 .0293 this is point zero seven zero six divided by two that is point zero three five three so we need to continue here that is again so this is actually cancelled out so two p gap is this is something like this point zero this is so basically p cap is 0 .0353 so what would be our margin of error this is 0 .0413 minus 0 .0353 this is 0 .006 so 0 .006 is equals to 2 .576 multiplied by under root of 0 .0413 we need to erase this to make it more clear.
02:30
Multiply by 1 -0 .0413 divided by n.
02:36
So 0 .062576 multiplied by 0 .0413 multiplied multiplied by 1 minus 0 .0413 this is 0 .04 under root of 0 .04 divided by n so under root of n divided by 0 .04 2 .576 divided by 0 .06 2 .576 divided by 0 .06 6 that is 42 .93 so what would be our sample size this is 42 .93 raised to power 2 multiplied by 0 .04 42 .93 raised to power 2 multiplied by 0 .04 is 73 .72 and sample size and is 74 so we need to continue here what would be our b part there is so this is 94 confidence level now we need to continue here p cap is 0 .3812 and q cap is 1 minus p cap is 1 minus 0 .3812.
04:07
We need to continue here...