Question

(a) A student is shown a video of a ball being dropped next to a long piece of measuring tape. The student imagines the origin to be located at the ball’s initial location, when t = 0, and records the list of positions shown in the table below. The time between each measurement of position is 0.10 s, as determined by watching the time signature on the video. Complete the following table by computing the average velocity between each set of subsequent positions, and then computing the average acceleration between each set of subsequent average velocities. (m) 0.00 -0.05 -0.18 -0.45 -0.83 -1.21 -1.78 -2.47 -3.25 -4.02 -5.01 -6.07 (b) Evaluate your average acceleration data. Was this likely a video of a ball falling in Earth’s gravitational field? Explain your conclusion.

          (a) A student is shown a video of a ball being dropped next to a
long piece of measuring tape.  The student imagines the
origin to be located at the ball’s initial location, when t = 0,
and records the list of positions shown in the table
below.  The time between each measurement of position is
0.10 s, as determined by watching the time signature on the
video. 
Complete the following table by computing the average velocity
between each set of subsequent positions, and then computing the
average acceleration between each set of subsequent average
velocities.
(m) 0.00 -0.05 -0.18 -0.45 -0.83 -1.21 -1.78 -2.47 -3.25 -4.02
-5.01 -6.07
(b) Evaluate your average acceleration data.  Was this
likely a video of a ball falling in Earth’s gravitational field?
Explain your conclusion.

Show more…

Added by Rachel C.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Supreeta N

04/27/2023

Step 1

First, we need to find the average velocity between each set of subsequent positions. The formula for average velocity is: $$v_{avg} = \frac{\Delta x}{\Delta t}$$ where $\Delta x$ is the change in position and $\Delta t$ is the change in time. Since the time Show more…

Show all steps

lock

Thanks for your feedback!

(a) A student is shown a video of a ball being dropped next to a long piece of measuring tape. The student imagines the origin to be located at the ball’s initial location, when t = 0, and records the list of positions shown in the table below. The time between each measurement of position is 0.10 s, as determined by watching the time signature on the video. Complete the following table by computing the average velocity between each set of subsequent positions, and then computing the average acceleration between each set of subsequent average velocities. (m) 0.00 -0.05 -0.18 -0.45 -0.83 -1.21 -1.78 -2.47 -3.25 -4.02 -5.01 -6.07 (b) Evaluate your average acceleration data. Was this likely a video of a ball falling in Earth’s gravitational field? Explain your conclusion.

Play audio

Feedback

Powered by NumerAI

Supreeta N and 73 other subject Physics 101 Mechanics educators are ready to help you.

Ask a new question

Labs

Want to see this concept in action?

NEW

Explore this concept interactively to see how it behaves as you change inputs.

View Labs

Key Concepts

Recommended Videos

Recommended Textbooks

Transcript

00:01 Hi, in this question we are given with a position and time.

00:03 Now we have to find the average velocity.

00:07 So average velocity between the subsequent position.

00:13 So subsequent position here this minus this, this minus this and this minus this.

00:23 So subtract go on subtracting all these values.

00:26 So we have the answer as it is 0 .5, 1 .3, 2 .7, 3 .3, then 3 .8, this is also 3 .8, 5 .7, 6 .9, 7 .8, 7 .7, 9 .9 and 10 .6.

00:52 Then we have the change in the acceleration is so average.

00:58 So we have i in this question we are given with a position and the time.

01:04 Now we have to find the average velocity.

01:07 So average velocity is obtained by subtracting these two for the subsequent position.

01:13 So we have so we have to subtract the position.

01:18 So we have it is 0 .05.

01:21 So one will be example is it is 0 .05 minus 0 divided by 0 .1, which is equal to so taking the counts, it is 0 .5.

01:34 So it is in meter per second.

01:35 So it is 0 .5.

01:38 Then this is 1 .3.

01:41 So this will be 2 .7.

01:44 This will be 3 .3 and this is 3 .8.

01:50 So this is also 3 .8.

01:52 Then this value is 5 .7, then 6 .9, then 7 .8, 7 .7.

02:05 So this is 9 .9 and the last is 10 .6...

Ace is your personal tutor. It breaks down any question with clear steps so you can learn.

Start Using Ace

Continue solving this problem

Create a free account to:

View full step-by-step solution
Ask follow-up questions with Ace AI
Save progress and study later