AaBbCcD Aeabechcn hbbCcOdEe Roln Sracing M ^ 7 2 Assuming the distribution is normally distributed; below are the mean and standard deviation of the behavioral problem scores for the sample and the population: (40 marks total) Population μ = 40,000 σ = N Sample μ = 180 N = 800 student has a score of 150 (Xi) compute the Z score for this student. (a) Suppose mean? (6 marks for steps and 2 marks for the answer) How do you interpret this student's score in terms of the distance to the sample mean? (no computation required) (b) What is the percentage of students in the sample who score below this student's score? (10 marks for steps and marks for the answer) (c) Compute the standard error for the population mean? (6 marks for steps and marks for the answer) (d) How many standard error units is the sample mean below the sampling distribution? (6 marks for steps and marks for the answer) (e) What is the probability of samples that score below the sample mean? (8 marks for steps and 2 marks for the answer)
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We are given that Xi = 150, and the population mean and standard deviation are μ = 184 and σ = 40, respectively. Plugging in these values, we get: Z = (150 - 184) / 40 = -0.85 Show more…
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