00:01
So for this problem, we have that the probability of a winning, probability of a winning, or probability of a for short, will be equal to the probability of a winning the first four matches, plus probability of a winning four in five matches, plus the probability of a winning 4 in 6 matches, plus the probability of a winning 4 in 7 matches.
01:04
So we have that the probability for each one of these events can be treated as a binomial probability, where we have that the probability that x equals a particular value, k, would be equal to n -chus k times p to the power of k, times 1 minus p to the power of n minus k, where n is the number of trials.
01:31
But basically, we have n changing for each one of these.
01:35
We'd have n equals 5, n equals 6, and n equals 7, respectively for each one of those probabilities.
01:43
So we'd have the overall probability that a wins will be equal to, let's see here, using that, using the probability density or mass function as indicated.
01:58
We'd have that, let's see here, we'd have for probability of a winning four matches, that would be 0 .46 to the power of 4...