Question

(a) Assuming some similarity between the mechanism of hydroformylation using HCo(CO)4 and HRh(CO)(PPh3)3 as catalysts, propose a mechanism for the conversion of RCH=CH2 to RCH2CH2CHO and explain what is happening in each step. (b) 'The regioselectivity of the hydroformylation of RCH=CH2 catalyzed by HRh(CO)(PPh3)3 drops when the temperature is increased.' Explain what is meant by this statement.

          (a) Assuming some similarity between the mechanism of hydroformylation using HCo(CO)4 and HRh(CO)(PPh3)3 as catalysts, propose a mechanism for the conversion of RCH=CH2 to RCH2CH2CHO and explain what is happening in each step.

(b) 'The regioselectivity of the hydroformylation of RCH=CH2 catalyzed by HRh(CO)(PPh3)3 drops when the temperature is increased.' Explain what is meant by this statement.
        
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(a) Assuming some similarity between the mechanism of hydroformylation using HCo(CO)4 and HRh(CO)(PPh3)3 as catalysts, propose a mechanism for the conversion of RCH=CH2 to RCH2CH2CHO and explain what is happening in each step.

(b) 'The regioselectivity of the hydroformylation of RCH=CH2 catalyzed by HRh(CO)(PPh3)3 drops when the temperature is increased.' Explain what is meant by this statement.

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Chemistry: Structure and Properties
Chemistry: Structure and Properties
Nivaldo Tro 2nd Edition
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Assuming some similarity between the mechanism of hydroformylation using HCo(CO)4 and HRh(CO)(PPh3)3 as catalysts, propose a mechanism for the conversion of RCH=CH2 to RCH2CH2CHO and explain what is happening in each step. The regioselectivity of the hydroformylation of RCH=CH2 catalyzed by HRh(CO)(PPh3)3 drops when the temperature is increased. Explain what is meant by this statement.
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00:01 Hey everyone the solution of this question is twice of h2 to get twice of h2 plus o2 now e plus s to get es complex right here ks it is you hear k1 and it is k minus 1 now es to get k2 p plus p plus e right p plus now the rate which is equal to rate which is equal to r max concentration of s divide by concentration of s plus km now v max divide by r max which is equal to maximum rate concentration of s is greater than substrate concentration now michelle constant right then we have all the values so we will put this value in the equation and we can calculate the rate so rate which is equal to 100 multiply with 0 .50 divide by 0 .50 plus 0 .50 so which is equal to 50 divide by 0 .60 so which is equal to 50 divide by 0 .65 which is equal to 76 .923...
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