00:01
Here our task is to find the equilibrium constant for the reaction.
00:07
So the reaction is 2 s -o -3, equilibrium with 2 s -o -2 plus o2.
00:18
We have already provided the amount of s -o -3 and the equilibrium, the concentration, not just the concentration, the amount of oxygen at equilibrium.
00:32
So we can calculate the amount of the concentration of so3.
00:40
Concentration of so3 can be calculator and it is already provided that the amount of so3 is 0 .66 more and it is contained in a container its volume is 2 litre.
00:58
So using these values we can easily calculate the concentration of sulfur trioxide.
01:04
Because the concentration will be equal to the amount of substance or in mall divided by the volume so here we can 0 .660 mall divided by 2 liter so this will give a value 0 .33 molar so this is a concentration of sulfur triopsyrso x .o3 so to find the equilibrium concentration of so3, so2 and oxygen, we can set up, we can create an ice table here.
01:50
So the reaction is 2 -so3, equilibrium with so2 plus o2.
02:02
When balancing it will be like this.
02:05
So the initial concentration, change in concentration, equilibrium concentration need to be find out.
02:11
So the initial concentration is 0 .33.
02:13
So it is 0 .33.
02:17
For 0 .02 and 0, it is 0.
02:20
And the change is 2x.
02:23
And it is plus 2x.
02:26
And it is x...