(a) At room temperature what is the strength of the electric field in a 12 -gauge copper wire (diameter 2.05 $\mathrm{mm}$ ) that is needed to cause a $2.75-$ A current to flow? (b) What field would be needed if the wire were made of silver instead?
Added by Steven D.
Step 1
05 mm. Given diameter, d = 2.05 mm Radius, r = d/2 = 2.05 mm / 2 = 1.025 mm = 0.001025 m Area, A = πr^2 = π(0.001025)^2 = 3.305 x 10^-6 m^2 Show more…
Show all steps
Your feedback will help us improve your experience
Hubert Agamasu and 95 other Physics 102 Electricity and Magnetism educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
(a) At room temperature, what is the strength of the electric field in a 12-gauge copper wire (diameter 2.05 mm) that is needed to cause a 4.50-A current to flow? (b) What field would be needed if the wire were made of silver instead?
Current, Resistance, and Electromotive Force
Resistivity
Ivan K.
A 14 gauge copper wire of diameter 1.628 $\mathrm{mm}$ carries a current of 12.5 $\mathrm{mA}$ (a) What is the potential difference across a 2.00 $\mathrm{m}$ length of the wire? (b) What would the potential difference in part (a) be if the wire were silver instead of copper, but all else was the same?
Recommended Textbooks
University Physics with Modern Physics
Physics: Principles with Applications
Fundamentals of Physics
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD