(a) At the .05 significance level, can you conclude that there is a difference in the mean selling Price (market price in dollars) of homes with a pool and homes without a pool? population
Added by Jazmine M.
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First, we need to formulate our null hypothesis (H0) and alternative hypothesis (H1). In this case, our null hypothesis would be that there is no difference in the mean selling price of homes with a pool and homes without a pool. The alternative hypothesis would Show more…
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Sale Prices for Houses The average sales price of new one-family houses in the Midwest is dollar 250,000 and in the South is dollar 253,400. A random sample of 40 houses in each region was examined with the following results. At the 0.05 level of significance, can it be concluded that the difference in mean sales price for the two regions is greater than dollar 3400 ? $$ \begin{array}{lcc}{} & {\text { South }} & {\text { Midwest }} \\ \hline \text { Sample size } & {40} & {40} \\ {\text { Sample mean }} & {\$ 261,500} & {\$ 248,200} \\ {\text { Population standard deviation }} & {\$ 10,500} & {\$ 12,000}\end{array} $$
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The average sales price of new one-family houses in the Midwest is $\$ 250,000$ and in the South is $\$ 253,400$. A random sample of 40 houses in each region was examined with the following results. At the 0.05 level of significance, can it be concluded that the difference in mean sales price for the two regions is greater than $\$ 3400 ?$ $$ \begin{array}{lll} & \text { South } & \text { Midwest } \\ \hline \text { Sample size } & 40 & 40 \\ \text { Sample mean } & \$ 261,500 & \$ 248,200 \\ \text { Population standard deviation } & \$ 10.500 & \$ 12.000 \end{array} $$
The prices of a random sample of homes in four areas of a certain city (Areas A, B, C, and D) were recorded and the following ANOVA table was obtained, and we would like to determine whether there is a difference in the mean price of homes among these four areas of the city at the significance level of 0.1. (Round your answers to 3 decimal places, if needed.)
Juan N.
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