60 \times 10^9 \mathrm{kg} \cdot \mathrm{m} / \mathrm{s}$.
Momentum (p) is given by the product of mass (m) and velocity (v): $p = mv$.
We are given the mass of the airplane, $m = 2.00 \times 10^4 \mathrm{kg}$, and the desired momentum, $p = 1.60 \times 10^9
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