00:01
For this problem on the topic of properties of pure substances, we are given refrigerant r22 in different states, and we are asked to calculate the phase in each of these states.
00:12
So for part a, we have r22 at a temperature of 50 degrees celsius, and a specific volume of 0 .05 cubic meters per kg.
00:31
Now we know the vapor -specific volume vg from our tables is 0 .1167 cubic meters per kg and since the specific volume for r22 in this case is greater than vg we have that the refrigerant is in a superheated vapor phase.
01:08
For part b we have r22 at a pressure of 1 megapascal and a temperature of 20 degrees celsius.
01:22
And again, if we go to our temperatures, or to our tables rather, we know that pg, the vapor pressure is 909 .9 kilopascals.
01:41
And since our pressure, p .g, is greater than pg.
01:47
We know that the r22 is in the phase of a compressed liquid...