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Hi there.
00:01
So for this problem, we have a bag of sugar that weights five pounds on earth.
00:15
So for this problem, we are asked, what would it weight in neutens on the moon, where free fall acceleration, we're given that the acceleration due to gravity on the moon is 1 over 6 times the gravitation, times the acceleration due to gravity on earth.
00:38
So the first thing that we need to do is to convert this from pounds to kilograms.
00:48
So by doing that, we just multiply this by a factor of conversion.
00:55
So that factor of conversion is that one kilogram is equal to 2 .2 pounds.
01:03
So from this, we obtain a value of 2 .27 kilograms.
01:20
And the bad will have weight on the earth.
01:26
Its weight on earth is equal to 2 .27 kilograms times the acceleration due to gravity on earth, that is approximately 9 .8 meters per second square.
01:41
So from this we obtain a value of 22 .27 newtoms.
01:52
So this is the weight of the back of sugar on earth in neutums.
01:58
And on the moon is going to be to be equal to this value that we obtain divided by 6, because that is the gravitational condition on the moon.
02:15
So if we divide this by six is equal to 3 .71 neutrons.
02:26
So that's the solution for the first part.
02:30
And for the final part, we need to repeat this for the weight of this back on jupiter, where we are told that, the gravitation on jupiter is equal to 2 .64 times the acceleration, the acceleration due to gravity on earth.
02:59
So to find the weight, we just multiplied the weight on the earth by that value of 2 .64...