0:00
Hi there.
00:01
So for this problem, we're told that a person who is 1 .2 meters tall, so the height we have in the figure, h, is that altitude 1 .2 meters.
00:19
Throats above with the speed that is given, and that speed, its magnitude, is equal to 11 meters per second.
00:30
At an angle of 19 degrees, that angle theta is 19 degrees.
00:41
So we need to use the acceleration due to gravity.
00:45
We need to consider that the acceleration due to gravity is equal to 10 meters per second square.
00:51
So the question is, what are the x and y components of the initial velocity? so let's call that the question a.
00:59
So to obtain the x component of the velocity or the speed, we just need to move.
01:06
The magnitude that we are given, that times the cosine of the angle because that angle is given with respect to the horizontal.
01:15
So that will be 11 meters per second, that times the cosine of 19 degrees.
01:22
So using our calculator, we obtain a value of 10 .4 meters per second.
01:33
So that's a solution for part a of this problem.
01:37
Now, for part b, we are asked about the, well, for the same question, we are asked about the white component of the initial velocity.
01:49
So it is the same question.
01:51
Okay, so that is the magnitude times the sign of the angle.
01:56
That will be 11 meters per second times the sign of 19 degrees.
02:04
So from this, using our calculator, we obtain a value of 3 .58 meters per second.
02:18
So that's a solution for the first question.
02:21
Now let's just do the power b, where we are at eric about what are the x and why components of the ball's velocity when it is at its maximum hot.
02:34
Now, for the x component, we will have the same value because we don't have any acceleration in the disruption.
02:44
So that will be the same value as before.
02:47
But for the y component, we know that at the maximum height, the speed, the y component of the speed, is momentarily equals to zero.
02:59
So that final y component of the speed is equal to 6.
03:04
So that's the solution for the second question in here.
03:11
Now for the next question, we are asked about what are the x and y components of the pulse velocity the instance before it hits the ground.
03:26
So, to solve this part of the problem, what we need to do is to first calculate the time that it takes to this ball to get to the ground, from the initial position to the ground.
03:44
So because we know that that final white component of the speed, the x component is going to remain the same value, but the white component, yes, the white component is determined by just the initial white component of the speed minus the acceleration due to gravity times the time.
04:05
So we need to determine that time.
04:07
And for that we use an equation from kinematics that is state that the change in the vertical position is equal to the initial white component of the speed times the time.
04:21
This minus 1 divided by 2 times the acceleration due to gravity times the time square.
04:28
So what we need to do is to simply substitute all of these values.
04:32
We know that the change in the vertical position is the final position that is going to.
04:38
To be zero and minus the initial position that is h.
04:43
So this will be just simply minus h...