A ball is thrown upward from the ground with an initial speed of 25 m/s; at the same instant, another ball is dropped from a building 15 m high. After how long will the balls be at the same height above the ground?
Added by John R.
Step 1
First, we need to find the time it takes for the ball that is thrown upward to reach its maximum height. We know that the acceleration due to gravity is -9.8 m/s^2 (negative because it's acting downward). We can use the equation of motion v = u + at, where v is Show more…
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A ball is thrown upward from the ground with an initial speed of $25 \mathrm{~m} / \mathrm{s} ;$ at the same instant, another ball is dropped from a building $15 \mathrm{~m}$ high. After how long will the balls be at the same height?
A ball is thrown upward from the ground with an ini- tial speed of 25 m/s; at the same instant, another ball is dropped from a building 15 m high. After how long will the balls be at the same height above the ground?
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